Zeph had some pastries.
27 of them were biscuits. The rest were cookies. He sold
56 of the biscuits and 6 cookies. In the end, he had 138 pastries left. How many more biscuits than cookies did he sell?
| |
Biscuits |
Cookies |
Comparing pastries
at first |
2x3 =
6 u |
5x3 =
15 u |
Before
|
6x1 =
6 u |
15 u |
Change
|
- 5x1 =
- 5 u |
- 6 |
After
|
1x1 =
1 u |
15 u - 6 |
The number of biscuits at first is repeated. Make the number of biscuits at first the same. LCM of 2 and 6 is 6.
Total number of pastries left
= 1 u + 15 u - 6
= 16 u - 6
16 u - 6 = 138
16 u = 138 + 6
16 u = 144
1 u = 144 ÷ 16 = 9
Number of more biscuits than cookies that Zeph sold
= 5 u - 6
= 5 x 9 - 6
= 45 - 6
= 39
Answer(s): 39
