Howard had some pastries.
35 of them were wafers. The rest were biscuits. He sold
56 of the wafers and 4 biscuits. In the end, he had 21 pastries left. How many more wafers than biscuits did he sell?
| |
Wafers |
Biscuits |
Comparing pastries
at first |
3x2 =
6 u |
2x2 =
4 u |
Before
|
6x1 =
6 u |
4 u |
Change
|
- 5x1 =
- 5 u |
- 4 |
After
|
1x1 =
1 u |
4 u - 4 |
The number of wafers at first is repeated. Make the number of wafers at first the same. LCM of 3 and 6 is 6.
Total number of pastries left
= 1 u + 4 u - 4
= 5 u - 4
5 u - 4 = 21
5 u = 21 + 4
5 u = 25
1 u = 25 ÷ 5 = 5
Number of more wafers than biscuits that Howard sold
= 5 u - 4
= 5 x 5 - 4
= 25 - 4
= 21
Answer(s): 21
