Japheth had some pastries.
35 of them were cookies. The rest were biscuits. He sold
56 of the cookies and 7 biscuits. In the end, he had 13 pastries left. How many more cookies than biscuits did he sell?
| |
Cookies |
Biscuits |
Comparing pastries
at first |
3x2 =
6 u |
2x2 =
4 u |
Before
|
6x1 =
6 u |
4 u |
Change
|
- 5x1 =
- 5 u |
- 7 |
After
|
1x1 =
1 u |
4 u - 7 |
The number of cookies at first is repeated. Make the number of cookies at first the same. LCM of 3 and 6 is 6.
Total number of pastries left
= 1 u + 4 u - 7
= 5 u - 7
5 u - 7 = 13
5 u = 13 + 7
5 u = 20
1 u = 20 ÷ 5 = 4
Number of more cookies than biscuits that Japheth sold
= 5 u - 7
= 5 x 4 - 7
= 20 - 7
= 13
Answer(s): 13
