Charlie had some pastries.
27 of them were croissants. The rest were macarons. He sold
56 of the croissants and 10 macarons. In the end, he had 102 pastries left. How many more croissants than macarons did he sell?
| |
Croissants |
Macarons |
Comparing pastries
at first |
2x3 =
6 u |
5x3 =
15 u |
Before
|
6x1 =
6 u |
15 u |
Change
|
- 5x1 =
- 5 u |
- 10 |
After
|
1x1 =
1 u |
15 u - 10 |
The number of croissants at first is repeated. Make the number of croissants at first the same. LCM of 2 and 6 is 6.
Total number of pastries left
= 1 u + 15 u - 10
= 16 u - 10
16 u - 10 = 102
16 u = 102 + 10
16 u = 112
1 u = 112 ÷ 16 = 7
Number of more croissants than macarons that Charlie sold
= 5 u - 10
= 5 x 7 - 10
= 35 - 10
= 25
Answer(s): 25
