Seth had $202 more money than Liam at first. After Seth spent
12 of his money to buy a blazer and Liam spent
14 of his money to buy a sweater, they had a total of $401 left. How much more did the blazer cost than the sweater?
| |
Seth |
Liam |
Comparing Seth and
Liam at first |
$202 more |
|
| Before |
2x2 |
$202 |
4x1 |
| Change |
- 1x2 |
- $101 |
- 1x1 |
| After |
1x2 |
$101 |
3x1 |
| |
Seth |
Liam |
| Before |
4 u + $202 |
4 u |
| Change |
- 2 u - $101 |
- 1 u |
| After |
2 u + $101 |
3 u |
LCM of 2 and 4 = 4
12 x 202 = 101
202 - 101 = 101
Total amount that Seth and Liam had in the end
= 2 u + 101 + 3 u
= 5 u + 101
5 u + 101 = 401
5 u = 401 - 101
5 u = 300
1 u = 300 ÷ 5 = 60
Amount paid more for the blazer than the sweater
= (2 u + 101) - 1 u
= 2 u - 1 u + 101
= 1 u + 101
= (1 x 60) + 101
= 60 + 101
= $161
Answer(s): $161
