Charlie had $369 more money than Pierre at first. After Charlie spent
23 of his money to buy a windbreaker and Pierre spent
15 of his money to buy a sweater, they had a total of $582 left. How much more did the windbreaker cost than the sweater?
| |
Charlie |
Pierre |
Comparing Charlie and
Pierre at first |
369 more |
|
| Before |
3x5 |
369 |
5x3 |
| Change |
- 2x5 |
- 246 |
- 1x3 |
| After |
1x5 |
123 |
4x3 |
| |
Charlie |
Pierre |
| Before |
15 u + 369 |
15 u |
| Change |
- 10 u - 246 |
- 3 u |
| After |
5 u + 123 |
12 u |
LCM of 3 and 5 = 15
23 x 369 = 246
369 - 246 = 123
Total amount that Charlie and Pierre had in the end
= 5 u + 123 + 12 u
= 17 u + 123
17 u + 123 = 582
17 u = 582 - 123
17 u = 459
1 u = 459 ÷ 17 = 27
Amount paid more for the windbreaker than the sweater
= (10 u + 246) - 3 u
= 10 u - 3 u + 246
= 7 u + 246
= (7 x 27) + 246
= 189 + 246
= $435
Answer: $435
