Daniel had $290 more money than Neave at first. After Daniel spent
12 of his money to buy a blazer and Neave spent
13 of his money to buy a coat, they had a total of $600 left. How much more did the blazer cost than the coat?
| |
Daniel |
Neave |
Comparing Daniel and
Neave at first |
$290 more |
|
| Before |
2x3 |
$290 |
3x2 |
| Change |
- 1x3 |
- $145 |
- 1x2 |
| After |
1x3 |
$145 |
2x2 |
| |
Daniel |
Neave |
| Before |
6 u + $290 |
6 u |
| Change |
- 3 u - $145 |
- 2 u |
| After |
3 u + $145 |
4 u |
LCM of 2 and 3 = 6
12 x 290 = 145
290 - 145 = 145
Total amount that Daniel and Neave had in the end
= 3 u + 145 + 4 u
= 7 u + 145
7 u + 145 = 600
7 u = 600 - 145
7 u = 455
1 u = 455 ÷ 7 = 65
Amount paid more for the blazer than the coat
= (3 u + 145) - 2 u
= 3 u - 2 u + 145
= 1 u + 145
= (1 x 65) + 145
= 65 + 145
= $210
Answer(s): $210
