Brandon had $294 more money than Gabriel at first. After Brandon spent
23 of his money to buy a sweater and Gabriel spent
15 of his money to buy a dress, they had a total of $438 left. How much more did the sweater cost than the dress?
| |
Brandon |
Gabriel |
Comparing Brandon and
Gabriel at first |
294 more |
|
| Before |
3x5 |
294 |
5x3 |
| Change |
- 2x5 |
- 196 |
- 1x3 |
| After |
1x5 |
98 |
4x3 |
| |
Brandon |
Gabriel |
| Before |
15 u + 294 |
15 u |
| Change |
- 10 u - 196 |
- 3 u |
| After |
5 u + 98 |
12 u |
LCM of 3 and 5 = 15
23 x 294 = 196
294 - 196 = 98
Total amount that Brandon and Gabriel had in the end
= 5 u + 98 + 12 u
= 17 u + 98
17 u + 98 = 438
17 u = 438 - 98
17 u = 340
1 u = 340 ÷ 17 = 20
Amount paid more for the sweater than the dress
= (10 u + 196) - 3 u
= 10 u - 3 u + 196
= 7 u + 196
= (7 x 20) + 196
= 140 + 196
= $336
Answer: $336
