Rael had $288 more money than Sean at first. After Rael spent
12 of his money to buy a dress and Sean spent
13 of his money to buy a sweater, they had a total of $487 left. How much more did the dress cost than the sweater?
| |
Rael |
Sean |
Comparing Rael and
Sean at first |
$288 more |
|
| Before |
2x3 |
$288 |
3x2 |
| Change |
- 1x3 |
- $144 |
- 1x2 |
| After |
1x3 |
$144 |
2x2 |
| |
Rael |
Sean |
| Before |
6 u + $288 |
6 u |
| Change |
- 3 u - $144 |
- 2 u |
| After |
3 u + $144 |
4 u |
LCM of 2 and 3 = 6
12 x 288 = 144
288 - 144 = 144
Total amount that Rael and Sean had in the end
= 3 u + 144 + 4 u
= 7 u + 144
7 u + 144 = 487
7 u = 487 - 144
7 u = 343
1 u = 343 ÷ 7 = 49
Amount paid more for the dress than the sweater
= (3 u + 144) - 2 u
= 3 u - 2 u + 144
= 1 u + 144
= (1 x 49) + 144
= 49 + 144
= $193
Answer(s): $193
