David had $288 more money than Pierre at first. After David spent
23 of his money to buy a blouse and Pierre spent
15 of his money to buy a shirt, they had a total of $589 left. How much more did the blouse cost than the shirt?
|
David |
Pierre |
Comparing David and Pierre at first |
288 more |
|
Before |
3x5 |
288 |
5x3 |
Change |
- 2x5 |
- 192 |
- 1x3 |
After |
1x5 |
96 |
4x3 |
|
David |
Pierre |
Before |
15 u + 288 |
15 u |
Change |
- 10 u - 192 |
- 3 u |
After |
5 u + 96 |
12 u |
LCM of 3 and 5 = 15
23 x 288 = 192
288 - 192 = 96
Total amount that David and Pierre had in the end
= 5 u + 96 + 12 u
= 17 u + 96
17 u + 96 = 589
17 u = 589 - 96
17 u = 493
1 u = 493 ÷ 17 = 29
Amount paid more for the blouse than the shirt
= (10 u + 192) - 3 u
= 10 u - 3 u + 192
= 7 u + 192
= (7 x 29) + 192
= 203 + 192
= $395
Answer: $395