Pierre had $345 more money than Tim at first. After Pierre spent
23 of his money to buy a blazer and Tim spent
15 of his money to buy a blouse, they had a total of $506 left. How much more did the blazer cost than the blouse?
| |
Pierre |
Tim |
Comparing Pierre and
Tim at first |
345 more |
|
| Before |
3x5 |
345 |
5x3 |
| Change |
- 2x5 |
- 230 |
- 1x3 |
| After |
1x5 |
115 |
4x3 |
| |
Pierre |
Tim |
| Before |
15 u + 345 |
15 u |
| Change |
- 10 u - 230 |
- 3 u |
| After |
5 u + 115 |
12 u |
LCM of 3 and 5 = 15
23 x 345 = 230
345 - 230 = 115
Total amount that Pierre and Tim had in the end
= 5 u + 115 + 12 u
= 17 u + 115
17 u + 115 = 506
17 u = 506 - 115
17 u = 391
1 u = 391 ÷ 17 = 23
Amount paid more for the blazer than the blouse
= (10 u + 230) - 3 u
= 10 u - 3 u + 230
= 7 u + 230
= (7 x 23) + 230
= 161 + 230
= $391
Answer: $391
