Riordan had $218 more money than Lee at first. After Riordan spent
12 of his money to buy a sweater and Lee spent
13 of his money to buy a skirt, they had a total of $417 left. How much more did the sweater cost than the skirt?
| |
Riordan |
Lee |
Comparing Riordan and
Lee at first |
$218 more |
|
| Before |
2x3 |
$218 |
3x2 |
| Change |
- 1x3 |
- $109 |
- 1x2 |
| After |
1x3 |
$109 |
2x2 |
| |
Riordan |
Lee |
| Before |
6 u + $218 |
6 u |
| Change |
- 3 u - $109 |
- 2 u |
| After |
3 u + $109 |
4 u |
LCM of 2 and 3 = 6
12 x 218 = 109
218 - 109 = 109
Total amount that Riordan and Lee had in the end
= 3 u + 109 + 4 u
= 7 u + 109
7 u + 109 = 417
7 u = 417 - 109
7 u = 308
1 u = 308 ÷ 7 = 44
Amount paid more for the sweater than the skirt
= (3 u + 109) - 2 u
= 3 u - 2 u + 109
= 1 u + 109
= (1 x 44) + 109
= 44 + 109
= $153
Answer(s): $153
