Paul had $458 more money than Oliver at first. After Paul spent
12 of his money to buy a jacket and Oliver spent
14 of his money to buy a sweater, they had a total of $519 left. How much more did the jacket cost than the sweater?
| |
Paul |
Oliver |
Comparing Paul and
Oliver at first |
$458 more |
|
| Before |
2x2 |
$458 |
4x1 |
| Change |
- 1x2 |
- $229 |
- 1x1 |
| After |
1x2 |
$229 |
3x1 |
| |
Paul |
Oliver |
| Before |
4 u + $458 |
4 u |
| Change |
- 2 u - $229 |
- 1 u |
| After |
2 u + $229 |
3 u |
LCM of 2 and 4 = 4
12 x 458 = 229
458 - 229 = 229
Total amount that Paul and Oliver had in the end
= 2 u + 229 + 3 u
= 5 u + 229
5 u + 229 = 519
5 u = 519 - 229
5 u = 290
1 u = 290 ÷ 5 = 58
Amount paid more for the jacket than the sweater
= (2 u + 229) - 1 u
= 2 u - 1 u + 229
= 1 u + 229
= (1 x 58) + 229
= 58 + 229
= $287
Answer(s): $287
