Julie had 30 more buttons than Xylia. After Julie gave away
25 of her buttons and Xylia gave away
23 of her buttons, Xylia had 50 less buttons than Julie. How many buttons did Julie have at first?
| |
Julie |
Xylia |
Comparing Julie and
Xylia at first |
30 more |
|
| Before |
5x3 |
+ 30 |
3x5 |
| Change |
- 2x3 |
- 12 |
- 2x5 |
| After |
3x3 |
+ 18 |
1x5 |
Comparing Julie and
Xylia in the end |
|
50 less |
| |
Julie |
Xylia |
| Before |
15 u + 30 |
15 u |
| Change |
- 6 u - 12 |
- 10 u |
| After |
9 u + 18 |
5 u |
25 x 30 = 12
30 - 12 = 18
Xylia had 50 less buttons than Julie in the end. So, if Xylia had another 50 buttons in the end, the number of buttons that Xylia and Julie each had would be the same.
9 u + 18 = 5 u + 50
9 u - 5 u = 50 - 18
4 u = 32
1 u = 32 ÷ 4 = 8
Number of buttons that Julie had at first
= 15 u + 30
= 15 x 8 + 30
= 120 + 30
= 150
Answer(s): 150
