Marion had 90 more buttons than Shannon. After Marion gave away
15 of her buttons and Shannon gave away
34 of her buttons, Shannon had 127 less buttons than Marion. How many buttons did Marion have at first?
| |
Marion |
Shannon |
Comparing Marion and
Shannon at first |
90 more |
|
| Before |
5x4 |
+ 90 |
4x5 |
| Change |
- 1x4 |
- 18 |
- 3x5 |
| After |
4x4 |
+ 72 |
1x5 |
Comparing Marion and
Shannon in the end |
|
127 less |
| |
Marion |
Shannon |
| Before |
20 u + 90 |
20 u |
| Change |
- 4 u - 18 |
- 15 u |
| After |
16 u + 72 |
5 u |
15 x 90 = 18
90 - 18 = 72
Shannon had 127 less buttons than Marion in the end. So, if Shannon had another 127 buttons in the end, the number of buttons that Shannon and Marion each had would be the same.
16 u + 72 = 5 u + 127
16 u - 5 u = 127 - 72
11 u = 55
1 u = 55 ÷ 11 = 5
Number of buttons that Marion had at first
= 20 u + 90
= 20 x 5 + 90
= 100 + 90
= 190
Answer(s): 190
