Xuan had 105 more buttons than Abi. After Xuan gave away
13 of her buttons and Abi gave away
34 of her buttons, Abi had 110 less buttons than Xuan. How many buttons did Xuan have at first?
| |
Xuan |
Abi |
Comparing Xuan and
Abi at first |
105 more |
|
| Before |
3x4 |
+ 105 |
4x3 |
| Change |
- 1x4 |
- 35 |
- 3x3 |
| After |
2x4 |
+ 70 |
1x3 |
Comparing Xuan and
Abi in the end |
|
110 less |
| |
Xuan |
Abi |
| Before |
12 u + 105 |
12 u |
| Change |
- 4 u - 35 |
- 9 u |
| After |
8 u + 70 |
3 u |
13 x 105 = 35
105 - 35 = 70
Abi had 110 less buttons than Xuan in the end. So, if Abi had another 110 buttons in the end, the number of buttons that Abi and Xuan each had would be the same.
8 u + 70 = 3 u + 110
8 u - 3 u = 110 - 70
5 u = 40
1 u = 40 ÷ 5 = 8
Number of buttons that Xuan had at first
= 12 u + 105
= 12 x 8 + 105
= 96 + 105
= 201
Answer(s): 201
