Joelle had 144 more buttons than Kimberly. After Joelle gave away
14 of her buttons and Kimberly gave away
35 of her buttons, Kimberly had 150 less buttons than Joelle. How many buttons did Joelle have at first?
| |
Joelle |
Kimberly |
Comparing Joelle and
Kimberly at first |
144 more |
|
| Before |
4x5 |
+ 144 |
5x4 |
| Change |
- 1x5 |
- 36 |
- 3x4 |
| After |
3x5 |
+ 108 |
2x4 |
Comparing Joelle and
Kimberly in the end |
|
150 less |
| |
Joelle |
Kimberly |
| Before |
20 u + 144 |
20 u |
| Change |
- 5 u - 36 |
- 12 u |
| After |
15 u + 108 |
8 u |
14 x 144 = 36
144 - 36 = 108
Kimberly had 150 less buttons than Joelle in the end. So, if Kimberly had another 150 buttons in the end, the number of buttons that Kimberly and Joelle each had would be the same.
15 u + 108 = 8 u + 150
15 u - 8 u = 150 - 108
7 u = 42
1 u = 42 ÷ 7 = 6
Number of buttons that Joelle had at first
= 20 u + 144
= 20 x 6 + 144
= 120 + 144
= 264
Answer(s): 264
