Marion had 115 more buttons than Raeann. After Marion gave away
15 of her buttons and Raeann gave away
13 of her buttons, Raeann had 112 less buttons than Marion. How many buttons did Marion have at first?
| |
Marion |
Raeann |
Comparing Marion and
Raeann at first |
115 more |
|
| Before |
5x3 |
+ 115 |
3x5 |
| Change |
- 1x3 |
- 23 |
- 1x5 |
| After |
4x3 |
+ 92 |
2x5 |
Comparing Marion and
Raeann in the end |
|
112 less |
| |
Marion |
Raeann |
| Before |
15 u + 115 |
15 u |
| Change |
- 3 u - 23 |
- 5 u |
| After |
12 u + 92 |
10 u |
15 x 115 = 23
115 - 23 = 92
Raeann had 112 less buttons than Marion in the end. So, if Raeann had another 112 buttons in the end, the number of buttons that Raeann and Marion each had would be the same.
12 u + 92 = 10 u + 112
12 u - 10 u = 112 - 92
2 u = 20
1 u = 20 ÷ 2 = 10
Number of buttons that Marion had at first
= 15 u + 115
= 15 x 10 + 115
= 150 + 115
= 265
Answer(s): 265
