23 of Tina's money was equal to
14 of Marion's money at first. After Tina spent $56 and Marion spent
35 of her money, Tina had
12 as much money as Marion.
- How much money did Marion have at first?
- How much money did Marion have in the end?
| |
Tina |
Marion |
Comparing Tina
and Marion at first |
3x5 =
15 u |
8x5 =
40 u |
| Before |
|
5x8 =
40 u |
| Change |
- $56 |
- 3x8 =
- 24 u |
| After |
|
2x8 =
16 u |
Comparing Tina
and Marion in the end |
1x8 =
8 u |
2x8 =
16 u |
23 Tina's money =
14 Marion's money
Make numerators the same.
23 Tina's money =
1x24x2 Marion's money
23 Tina's money =
28 Marion's money
Tina's money : Marion's money = 3 : 8
The amount that Marion had at first is repeated. Make the amount that Marion had at first the same. LCM of 8 and 5 is 40.
Amount that Tina spent
= 15 u - 8 u
= 7 u
7 u = 56
1 u = 56 ÷ 7 = 8
(a)
Amount that Marion had at first
= 40 u
= 40 x 8
= $320
(b)
Amount that Marion had in the end
= 16 u
= 16 x 8
= $128
Answer(s): (a) $320; (b) $128
