13 of Sabrina's money was equal to
14 of Hilda's money at first. After Sabrina spent $110 and Hilda spent
25 of her money, Sabrina had
13 as much money as Hilda.
- How much money did Hilda have at first?
- How much money did Hilda have in the end?
| |
Sabrina |
Hilda |
Comparing Sabrina
and Hilda at first |
3x5 =
15 u |
4x5 =
20 u |
| Before |
|
5x4 =
20 u |
| Change |
- $110 |
- 2x4 =
- 8 u |
| After |
|
3x4 =
12 u |
Comparing Sabrina
and Hilda in the end |
1x4 =
4 u |
3x4 =
12 u |
13 Sabrina's money =
14 Hilda's money
Make numerators the same.
13 Sabrina's money =
1x14x1 Hilda's money
13 Sabrina's money =
14 Hilda's money
Sabrina's money : Hilda's money = 3 : 4
The amount that Hilda had at first is repeated. Make the amount that Hilda had at first the same. LCM of 4 and 5 is 20.
Amount that Sabrina spent
= 15 u - 4 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
(a)
Amount that Hilda had at first
= 20 u
= 20 x 10
= $200
(b)
Amount that Hilda had in the end
= 12 u
= 12 x 10
= $120
Answer(s): (a) $200; (b) $120
