14 of Shannon's money was equal to
13 of Hazel's money at first. After Shannon spent $91 and Hazel spent
14 of her money, Shannon had
13 as much money as Hazel.
- How much money did Hazel have at first?
- How much money did Hazel have in the end?
| |
Shannon |
Hazel |
Comparing Shannon
and Hazel at first |
4x4 =
16 u |
3x4 =
12 u |
| Before |
|
4x3 =
12 u |
| Change |
- $91 |
- 1x3 =
- 3 u |
| After |
|
3x3 =
9 u |
Comparing Shannon
and Hazel in the end |
1x3 =
3 u |
3x3 =
9 u |
14 Shannon's money =
13 Hazel's money
Make numerators the same.
14 Shannon's money =
1x13x1 Hazel's money
14 Shannon's money =
13 Hazel's money
Shannon's money : Hazel's money = 4 : 3
The amount that Hazel had at first is repeated. Make the amount that Hazel had at first the same. LCM of 3 and 4 is 12.
Amount that Shannon spent
= 16 u - 3 u
= 13 u
13 u = 91
1 u = 91 ÷ 13 = 7
(a)
Amount that Hazel had at first
= 12 u
= 12 x 7
= $84
(b)
Amount that Hazel had in the end
= 9 u
= 9 x 7
= $63
Answer(s): (a) $84; (b) $63
