13 of Betty's money was equal to
14 of Min's money at first. After Betty spent $40 and Min spent
13 of her money, Betty had
12 as much money as Min.
- How much money did Min have at first?
- How much money did Min have in the end?
| |
Betty |
Min |
Comparing Betty
and Min at first |
3x3 =
9 u |
4x3 =
12 u |
| Before |
|
3x4 =
12 u |
| Change |
- $40 |
- 1x4 =
- 4 u |
| After |
|
2x4 =
8 u |
Comparing Betty
and Min in the end |
1x4 =
4 u |
2x4 =
8 u |
13 Betty's money =
14 Min's money
Make numerators the same.
13 Betty's money =
1x14x1 Min's money
13 Betty's money =
14 Min's money
Betty's money : Min's money = 3 : 4
The amount that Min had at first is repeated. Make the amount that Min had at first the same. LCM of 4 and 3 is 12.
Amount that Betty spent
= 9 u - 4 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
(a)
Amount that Min had at first
= 12 u
= 12 x 8
= $96
(b)
Amount that Min had in the end
= 8 u
= 8 x 8
= $64
Answer(s): (a) $96; (b) $64
