12 of Jade's money was equal to
13 of Hilda's money at first. After Jade spent $77 and Hilda spent
25 of her money, Jade had
13 as much money as Hilda.
- How much money did Hilda have at first?
- How much money did Hilda have in the end?
| |
Jade |
Hilda |
Comparing Jade
and Hilda at first |
2x5 =
10 u |
3x5 =
15 u |
| Before |
|
5x3 =
15 u |
| Change |
- $77 |
- 2x3 =
- 6 u |
| After |
|
3x3 =
9 u |
Comparing Jade
and Hilda in the end |
1x3 =
3 u |
3x3 =
9 u |
12 Jade's money =
13 Hilda's money
Make numerators the same.
12 Jade's money =
1x13x1 Hilda's money
12 Jade's money =
13 Hilda's money
Jade's money : Hilda's money = 2 : 3
The amount that Hilda had at first is repeated. Make the amount that Hilda had at first the same. LCM of 3 and 5 is 15.
Amount that Jade spent
= 10 u - 3 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
(a)
Amount that Hilda had at first
= 15 u
= 15 x 11
= $165
(b)
Amount that Hilda had in the end
= 9 u
= 9 x 11
= $99
Answer(s): (a) $165; (b) $99
