16 of Kimberly's money was equal to
15 of Jaslyn's money at first. After Kimberly spent $78 and Jaslyn spent
13 of her money, Kimberly had
12 as much money as Jaslyn.
- How much money did Jaslyn have at first?
- How much money did Jaslyn have in the end?
| |
Kimberly |
Jaslyn |
Comparing Kimberly
and Jaslyn at first |
6x3 =
18 u |
5x3 =
15 u |
| Before |
|
3x5 =
15 u |
| Change |
- $78 |
- 1x5 =
- 5 u |
| After |
|
2x5 =
10 u |
Comparing Kimberly
and Jaslyn in the end |
1x5 =
5 u |
2x5 =
10 u |
16 Kimberly's money =
15 Jaslyn's money
Make numerators the same.
16 Kimberly's money =
1x15x1 Jaslyn's money
16 Kimberly's money =
15 Jaslyn's money
Kimberly's money : Jaslyn's money = 6 : 5
The amount that Jaslyn had at first is repeated. Make the amount that Jaslyn had at first the same. LCM of 5 and 3 is 15.
Amount that Kimberly spent
= 18 u - 5 u
= 13 u
13 u = 78
1 u = 78 ÷ 13 = 6
(a)
Amount that Jaslyn had at first
= 15 u
= 15 x 6
= $90
(b)
Amount that Jaslyn had in the end
= 10 u
= 10 x 6
= $60
Answer(s): (a) $90; (b) $60
