45 of Kylie's money was equal to
12 of Roshel's money at first. After Kylie spent $33 and Roshel spent
14 of her money, Kylie had
13 as much money as Roshel.
- How much money did Roshel have at first?
- How much money did Roshel have in the end?
| |
Kylie |
Roshel |
Comparing Kylie
and Roshel at first |
5x1 =
5 u |
8x1 =
8 u |
| Before |
|
4x2 =
8 u |
| Change |
- $33 |
- 1x2 =
- 2 u |
| After |
|
3x2 =
6 u |
Comparing Kylie
and Roshel in the end |
1x2 =
2 u |
3x2 =
6 u |
45 Kylie's money =
12 Roshel's money
Make numerators the same.
45 Kylie's money =
1x42x4 Roshel's money
45 Kylie's money =
48 Roshel's money
Kylie's money : Roshel's money = 5 : 8
The amount that Roshel had at first is repeated. Make the amount that Roshel had at first the same. LCM of 8 and 4 is 8.
Amount that Kylie spent
= 5 u - 2 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
(a)
Amount that Roshel had at first
= 8 u
= 8 x 11
= $88
(b)
Amount that Roshel had in the end
= 6 u
= 6 x 11
= $66
Answer(s): (a) $88; (b) $66
