13 of Lucy's money was equal to
12 of Xylia's money at first. After Lucy spent $26 and Xylia spent
35 of her money, Lucy had
12 as much money as Xylia.
- How much money did Xylia have at first?
- How much money did Xylia have in the end?
| |
Lucy |
Xylia |
Comparing Lucy
and Xylia at first |
3x5 =
15 u |
2x5 =
10 u |
| Before |
|
5x2 =
10 u |
| Change |
- $26 |
- 3x2 =
- 6 u |
| After |
|
2x2 =
4 u |
Comparing Lucy
and Xylia in the end |
1x2 =
2 u |
2x2 =
4 u |
13 Lucy's money =
12 Xylia's money
Make numerators the same.
13 Lucy's money =
1x12x1 Xylia's money
13 Lucy's money =
12 Xylia's money
Lucy's money : Xylia's money = 3 : 2
The amount that Xylia had at first is repeated. Make the amount that Xylia had at first the same. LCM of 2 and 5 is 10.
Amount that Lucy spent
= 15 u - 2 u
= 13 u
13 u = 26
1 u = 26 ÷ 13 = 2
(a)
Amount that Xylia had at first
= 10 u
= 10 x 2
= $20
(b)
Amount that Xylia had in the end
= 4 u
= 4 x 2
= $8
Answer(s): (a) $20; (b) $8
