14 of Kimberly's money was equal to
13 of Yen's money at first. After Kimberly spent $102 and Yen spent
35 of her money, Kimberly had
12 as much money as Yen.
- How much money did Yen have at first?
- How much money did Yen have in the end?
| |
Kimberly |
Yen |
Comparing Kimberly
and Yen at first |
4x5 =
20 u |
3x5 =
15 u |
| Before |
|
5x3 =
15 u |
| Change |
- $102 |
- 3x3 =
- 9 u |
| After |
|
2x3 =
6 u |
Comparing Kimberly
and Yen in the end |
1x3 =
3 u |
2x3 =
6 u |
14 Kimberly's money =
13 Yen's money
Make numerators the same.
14 Kimberly's money =
1x13x1 Yen's money
14 Kimberly's money =
13 Yen's money
Kimberly's money : Yen's money = 4 : 3
The amount that Yen had at first is repeated. Make the amount that Yen had at first the same. LCM of 3 and 5 is 15.
Amount that Kimberly spent
= 20 u - 3 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
(a)
Amount that Yen had at first
= 15 u
= 15 x 6
= $90
(b)
Amount that Yen had in the end
= 6 u
= 6 x 6
= $36
Answer(s): (a) $90; (b) $36
