14 of Kimberly's money was equal to
13 of Tina's money at first. After Kimberly spent $65 and Tina spent
14 of her money, Kimberly had
13 as much money as Tina.
- How much money did Tina have at first?
- How much money did Tina have in the end?
| |
Kimberly |
Tina |
Comparing Kimberly
and Tina at first |
4x4 =
16 u |
3x4 =
12 u |
| Before |
|
4x3 =
12 u |
| Change |
- $65 |
- 1x3 =
- 3 u |
| After |
|
3x3 =
9 u |
Comparing Kimberly
and Tina in the end |
1x3 =
3 u |
3x3 =
9 u |
14 Kimberly's money =
13 Tina's money
Make numerators the same.
14 Kimberly's money =
1x13x1 Tina's money
14 Kimberly's money =
13 Tina's money
Kimberly's money : Tina's money = 4 : 3
The amount that Tina had at first is repeated. Make the amount that Tina had at first the same. LCM of 3 and 4 is 12.
Amount that Kimberly spent
= 16 u - 3 u
= 13 u
13 u = 65
1 u = 65 ÷ 13 = 5
(a)
Amount that Tina had at first
= 12 u
= 12 x 5
= $60
(b)
Amount that Tina had in the end
= 9 u
= 9 x 5
= $45
Answer(s): (a) $60; (b) $45
