Shannon and Marion had $136. Marion had $2 more than Shannon. Shannon spent 3 times as much as Marion and was left with
23 as much as Marion. How much did Marion spend less than Shannon?
| |
Make p the same
(1) x 3 = (3) |
Shannon
(1) |
Marion
(2) |
Make p the same
(2) x 2 = (4) |
Total
|
Comparing Shannon
and Marion at first |
|
|
$2 more |
|
$136 |
| Before |
$201 |
$67 |
$69 |
$138 |
|
| Change |
- 9 u |
- 3 u |
- 1 u |
- 2 u |
|
| After |
6 p |
2 p |
3 p |
6 p |
|
Amount that Shannon had at first
= (136 - 2) ÷ 2
= 134 ÷ 2
= $67
Amount that Marion had at first
= 67 + 2
= $69
67 - 3 u = 2 p --- (1)
69 - 1 u = 3 p --- (2)
Make p the same.
(1)
x 3
201 - 9 u =
6 p --- (3)
(2)
x 2
138 - 2 u =
6 p --- (4)
(4) = (3)
138 - 2 u = 201 - 9 u
9 u - 2 u = 201 - 138
7 u = 63
1 u = 63 ÷ 7 = 9
Amount that Marion spent less than Shannon
= 3 u - 1 u
= 2 u
= 2 x 9
= $18
Answer(s): $18
