Lee has a total of 40 of yellow and black markers.
16 of the yellow markers and half of the black markers are new. How many of his black markers are new if he has a total of 8 new markers?
|
Yellow markers |
Black markers |
Total |
Total |
6 u |
2 p |
40 |
New |
1 u |
1 p |
8 |
Old |
5 u |
1 p |
32 |
Number of old markers
= 40 - 8
= 32
1 u + 1 p = 8 --- (1)
5 u + 1 p = 32 --- (2)
(2) - (1)
(5 u + 1 p) - (1 u + 1 p) = 32 - 8
5 u - 1 u = 24
4 u = 24
1 u = 24 ÷ 4 = 6
Number of new black markers
= 8 - 1 u
= 8 - 6
= 2
Answer(s): 2