Daniel has a total of 60 of blue and white markers.
14 of the blue markers and half of the white markers are new. How many of his white markers are new if he has a total of 18 new markers?
| |
Blue markers |
White markers |
Total |
| Total |
4 u |
2 p |
60 |
| New |
1 u |
1 p |
18 |
| Old |
3 u |
1 p |
42 |
Number of old markers
= 60 - 18
= 42
1 u + 1 p = 18 --- (1)
3 u + 1 p = 42 --- (2)
(2) - (1)
(3 u + 1 p) - (1 u + 1 p) = 42 - 18
3 u - 1 u = 24
2 u = 24
1 u = 24 ÷ 2 = 12
Number of new white markers
= 18 - 1 u
= 18 - 12
= 6
Answer(s): 6
