The number of five-cent coins in a bag was
13 the number of ten-cent coins. Ian took out 24 ten-cent coins and exchanged them for five-cent coins. Then he put the money back into the bag. The number of ten-cent coins became
38 the number of five-cent coins. How much money was there in the bag?
|
Make u the same (1)x3 = (3) |
5-cent (1) |
10-cent (2) |
Before |
3 u |
1 u |
3 u |
Change |
+ 144 |
+ 48 |
- 24 |
After |
24 p |
8 p |
3 p |
Value of 10-cent coins to be exchanged to 5-cent coins
= 24 x 10
= 240
Number of 5-cent coins to be exchanged from the 10-cent coins
= 240 ÷ 5
= 48
(3) = (2)
24 p - 144 = 3 p + 24
24 p - 3 p = 24 + 144
21 p = 168
1 p = 168 ÷ 21 = 8
Number of 5-cent coins in the end
= 8 p
= 8 p x 8
= 64
Value of 5-cent coins in the end
= 64 x 5
= 320¢
Number of 10-cent coins in the end
= 3 p
= 3 x 8
= 24
Value of 10-cent coins in the end
= 24 x 10
= 240¢
Total value of coins
= 320 + 240
= 560¢
$1 = 100¢
560¢ = $5.60
Answer(s): $5.60