The number of five-cent coins in a tin can was ¹₄ the number of fifty-cent coins. Cole took out 17 fifty-cent coins and exchanged them for five-cent coins. Then he put the money back into the tin can. The number of fifty-cent coins became ³₅ the number of five-cent coins. How much money was there in the tin can?

	Make u the same (1)x4 = (3)	5-cent (1)	50-cent (2)
Before	4 u	1 u	4 u
Change	+ 680	+ 170	- 17
After	20 p	5 p	3 p

Value of 50-cent coins to be exchanged to 5-cent coins
= 17 x 50
= 850

Number of 5-cent coins to be exchanged from the 50-cent coins
= 850 ÷ 5
= 170

(3) = (2)
20 p - 680 = 3 p + 17
20 p - 3 p = 17 + 680
17 p = 697

1 p = 697 ÷ 17 = 41

Number of 5-cent coins in the end
= 5 p
= 5 p x 41
= 205

Value of 5-cent coins in the end
= 205 x 5
= 1025¢

Number of 50-cent coins in the end
= 3 p
= 3 x 41
= 123

Value of 50-cent coins in the end
= 123 x 50
= 6150¢

Total value of coins
= 1025 + 6150
= 7175¢

$1 = 100¢
7175¢ = $71.75 

Answer(s): $71.75