The number of five-cent coins in a tin can was
15 the number of ten-cent coins. Elijah took out 22 ten-cent coins and exchanged them for five-cent coins. Then he put the money back into the tin can. The number of ten-cent coins became
35 the number of five-cent coins. How much money was there in the tin can?
|
Make u the same (1)x5 = (3) |
5-cent (1) |
10-cent (2) |
Before |
5 u |
1 u |
5 u |
Change |
+ 220 |
+ 44 |
- 22 |
After |
25 p |
5 p |
3 p |
Value of 10-cent coins to be exchanged to 5-cent coins
= 22 x 10
= 220
Number of 5-cent coins to be exchanged from the 10-cent coins
= 220 ÷ 5
= 44
(3) = (2)
25 p - 220 = 3 p + 22
25 p - 3 p = 22 + 220
22 p = 242
1 p = 242 ÷ 22 = 11
Number of 5-cent coins in the end
= 5 p
= 5 p x 11
= 55
Value of 5-cent coins in the end
= 55 x 5
= 275¢
Number of 10-cent coins in the end
= 3 p
= 3 x 11
= 33
Value of 10-cent coins in the end
= 33 x 10
= 330¢
Total value of coins
= 275 + 330
= 605¢
$1 = 100¢
605¢ = $6.05
Answer(s): $6.05