The number of five-cent coins in a pouch was
14 the number of twenty-cent coins. Warren took out 21 twenty-cent coins and exchanged them for five-cent coins. Then he put the money back into the pouch. The number of twenty-cent coins became
35 the number of five-cent coins. How much money was there in the pouch?
|
Make u the same (1)x4 = (3) |
5-cent (1) |
20-cent (2) |
Before |
4 u |
1 u |
4 u |
Change |
+ 336 |
+ 84 |
- 21 |
After |
20 p |
5 p |
3 p |
Value of 20-cent coins to be exchanged to 5-cent coins
= 21 x 20
= 420
Number of 5-cent coins to be exchanged from the 20-cent coins
= 420 ÷ 5
= 84
(3) = (2)
20 p - 336 = 3 p + 21
20 p - 3 p = 21 + 336
17 p = 357
1 p = 357 ÷ 17 = 21
Number of 5-cent coins in the end
= 5 p
= 5 p x 21
= 105
Value of 5-cent coins in the end
= 105 x 5
= 525¢
Number of 20-cent coins in the end
= 3 p
= 3 x 21
= 63
Value of 20-cent coins in the end
= 63 x 20
= 1260¢
Total value of coins
= 525 + 1260
= 1785¢
$1 = 100¢
1785¢ = $17.85
Answer(s): $17.85