The number of five-cent coins in a bag was ¹₄ the number of ten-cent coins. Pierre took out 22 ten-cent coins and exchanged them for five-cent coins. Then he put the money back into the bag. The number of ten-cent coins became ²₅ the number of five-cent coins. How much money was there in the bag?

	Make u the same (1)x4 = (3)	5-cent (1)	10-cent (2)
Before	4 u	1 u	4 u
Change	+ 176	+ 44	- 22
After	20 p	5 p	2 p

Value of 10-cent coins to be exchanged to 5-cent coins
= 22 x 10
= 220

Number of 5-cent coins to be exchanged from the 10-cent coins
= 220 ÷ 5
= 44

(3) = (2)
20 p - 176 = 2 p + 22
20 p - 2 p = 22 + 176
18 p = 198

1 p = 198 ÷ 18 = 11

Number of 5-cent coins in the end
= 5 p
= 5 p x 11
= 55

Value of 5-cent coins in the end
= 55 x 5
= 275¢

Number of 10-cent coins in the end
= 2 p
= 2 x 11
= 22

Value of 10-cent coins in the end
= 22 x 10
= 220¢

Total value of coins
= 275 + 220
= 495¢

$1 = 100¢
495¢ = $4.95 

Answer(s): $4.95