The number of ten-cent coins in a tin can was ¹₅ the number of twenty-cent coins. Bryan took out 22 twenty-cent coins and exchanged them for ten-cent coins. Then he put the money back into the tin can. The number of twenty-cent coins became ³₅ the number of ten-cent coins. How much money was there in the tin can?

	Make u the same (1)x5 = (3)	10-cent (1)	20-cent (2)
Before	5 u	1 u	5 u
Change	+ 220	+ 44	- 22
After	25 p	5 p	3 p

Value of 20-cent coins to be exchanged to 10-cent coins
= 22 x 20
= 440

Number of 10-cent coins to be exchanged from the 20-cent coins
= 440 ÷ 10
= 44

(3) = (2)
25 p - 220 = 3 p + 22
25 p - 3 p = 22 + 220
22 p = 242

1 p = 242 ÷ 22 = 11

Number of 10-cent coins in the end
= 5 p
= 5 p x 11
= 55

Value of 10-cent coins in the end
= 55 x 10
= 550¢

Number of 20-cent coins in the end
= 3 p
= 3 x 11
= 33

Value of 20-cent coins in the end
= 33 x 20
= 660¢

Total value of coins
= 550 + 660
= 1210¢

$1 = 100¢
1210¢ = $12.10 

Answer(s): $12.10