The number of ten-cent coins in a pouch was
13 the number of fifty-cent coins. Nick took out 19 fifty-cent coins and exchanged them for ten-cent coins. Then he put the money back into the pouch. The number of fifty-cent coins became
58 the number of ten-cent coins. How much money was there in the pouch?
|
Make u the same (1)x3 = (3) |
10-cent (1) |
50-cent (2) |
Before |
3 u |
1 u |
3 u |
Change |
+ 285 |
+ 95 |
- 19 |
After |
24 p |
8 p |
5 p |
Value of 50-cent coins to be exchanged to 10-cent coins
= 19 x 50
= 950
Number of 10-cent coins to be exchanged from the 50-cent coins
= 950 ÷ 10
= 95
(3) = (2)
24 p - 285 = 5 p + 19
24 p - 5 p = 19 + 285
19 p = 304
1 p = 304 ÷ 19 = 16
Number of 10-cent coins in the end
= 8 p
= 8 p x 16
= 128
Value of 10-cent coins in the end
= 128 x 10
= 1280¢
Number of 50-cent coins in the end
= 5 p
= 5 x 16
= 80
Value of 50-cent coins in the end
= 80 x 50
= 4000¢
Total value of coins
= 1280 + 4000
= 5280¢
$1 = 100¢
5280¢ = $52.80
Answer(s): $52.80