The number of five-cent coins in a tin can was ¹₃ the number of twenty-cent coins. Sean took out 23 twenty-cent coins and exchanged them for five-cent coins. Then he put the money back into the tin can. The number of twenty-cent coins became ²₅ the number of five-cent coins. How much money was there in the tin can?

	Make u the same (1)x3 = (3)	5-cent (1)	20-cent (2)
Before	3 u	1 u	3 u
Change	+ 276	+ 92	- 23
After	15 p	5 p	2 p

Value of 20-cent coins to be exchanged to 5-cent coins
= 23 x 20
= 460

Number of 5-cent coins to be exchanged from the 20-cent coins
= 460 ÷ 5
= 92

(3) = (2)
15 p - 276 = 2 p + 23
15 p - 2 p = 23 + 276
13 p = 299

1 p = 299 ÷ 13 = 23

Number of 5-cent coins in the end
= 5 p
= 5 p x 23
= 115

Value of 5-cent coins in the end
= 115 x 5
= 575¢

Number of 20-cent coins in the end
= 2 p
= 2 x 23
= 46

Value of 20-cent coins in the end
= 46 x 20
= 920¢

Total value of coins
= 575 + 920
= 1495¢

$1 = 100¢
1495¢ = $14.95 

Answer(s): $14.95