The number of five-cent coins in a tin can was
13 the number of fifty-cent coins. Luis took out 24 fifty-cent coins and exchanged them for five-cent coins. Then he put the money back into the tin can. The number of fifty-cent coins became
35 the number of five-cent coins. How much money was there in the tin can?
|
Make u the same (1)x3 = (3) |
5-cent (1) |
50-cent (2) |
Before |
3 u |
1 u |
3 u |
Change |
+ 720 |
+ 240 |
- 24 |
After |
15 p |
5 p |
3 p |
Value of 50-cent coins to be exchanged to 5-cent coins
= 24 x 50
= 1200
Number of 5-cent coins to be exchanged from the 50-cent coins
= 1200 ÷ 5
= 240
(3) = (2)
15 p - 720 = 3 p + 24
15 p - 3 p = 24 + 720
12 p = 744
1 p = 744 ÷ 12 = 62
Number of 5-cent coins in the end
= 5 p
= 5 p x 62
= 310
Value of 5-cent coins in the end
= 310 x 5
= 1550¢
Number of 50-cent coins in the end
= 3 p
= 3 x 62
= 186
Value of 50-cent coins in the end
= 186 x 50
= 9300¢
Total value of coins
= 1550 + 9300
= 10850¢
$1 = 100¢
10850¢ = $108.50
Answer(s): $108.50