The number of five-cent coins in a tin can was ¹₄ the number of ten-cent coins. Paul took out 24 ten-cent coins and exchanged them for five-cent coins. Then he put the money back into the tin can. The number of ten-cent coins became ⁵₈ the number of five-cent coins. How much money was there in the tin can?

	Make u the same (1)x4 = (3)	5-cent (1)	10-cent (2)
Before	4 u	1 u	4 u
Change	+ 192	+ 48	- 24
After	32 p	8 p	5 p

Value of 10-cent coins to be exchanged to 5-cent coins
= 24 x 10
= 240

Number of 5-cent coins to be exchanged from the 10-cent coins
= 240 ÷ 5
= 48

(3) = (2)
32 p - 192 = 5 p + 24
32 p - 5 p = 24 + 192
27 p = 216

1 p = 216 ÷ 27 = 8

Number of 5-cent coins in the end
= 8 p
= 8 p x 8
= 64

Value of 5-cent coins in the end
= 64 x 5
= 320¢

Number of 10-cent coins in the end
= 5 p
= 5 x 8
= 40

Value of 10-cent coins in the end
= 40 x 10
= 400¢

Total value of coins
= 320 + 400
= 720¢

$1 = 100¢
720¢ = $7.20 

Answer(s): $7.20