Three girls, Joelle, Emma and Kylie had a total of 3240 coins. Some exchanges were made. First, Joelle gave Emma as many coins as Emma had. After that, Emma gave
15 of whatever she had then to Kylie. Finally, Kylie gave
14 of whatever she had to Joelle. As a result, they each had the same number of coins. How many coins did Joelle have at first?
|
Joelle |
Emma |
Kylie |
Total |
Before 1 |
? |
1 u |
|
3240 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
3240 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
4 boxes |
3240 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
3 boxes |
|
After 3 |
1 group |
1 group |
1 group |
3240 |
3 groups = 3240
1 group = 3240 ÷ 3 = 1080
1 group = 3 boxes 3 boxes = 1080
1 box = 1080 ÷ 3 = 360
4 p = 1 group
1 p = 1080 ÷ 4 = 270
5 p = 5 x 270 = 1350
5 p = 2 u
2 u = 1350
1 u = 1350 ÷ 2 = 675
Number of coins that Joelle had at first
= 1 group - 1 box + 1 u
= 1080 - 360 + 675
= 1395
Answer(s): 1395