Three girls, Jean, Raeann and Vanessa had a total of 2430 coins. Some exchanges were made. First, Jean gave Raeann as many coins as Raeann had. After that, Raeann gave
14 of whatever she had then to Vanessa. Finally, Vanessa gave
14 of whatever she had to Jean. As a result, they each had the same number of coins. How many coins did Jean have at first?
|
Jean |
Raeann |
Vanessa |
Total |
Before 1 |
? |
1 u |
|
2430 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
2430 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
4 boxes |
2430 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
3 boxes |
|
After 3 |
1 group |
1 group |
1 group |
2430 |
3 groups = 2430
1 group = 2430 ÷ 3 = 810
1 group = 3 boxes 3 boxes = 810
1 box = 810 ÷ 3 = 270
3 p = 1 group
1 p = 810 ÷ 3 = 270
4 p = 4 x 270 = 1080
4 p = 2 u
2 u = 1080
1 u = 1080 ÷ 2 = 540
Number of coins that Jean had at first
= 1 group - 1 box + 1 u
= 810 - 270 + 540
= 1080
Answer(s): 1080