Three girls, Tiffany, Roshel and Min had a total of 5400 coins. Some exchanges were made. First, Tiffany gave Roshel as many coins as Roshel had. After that, Roshel gave
14 of whatever she had then to Min. Finally, Min gave
15 of whatever she had to Tiffany. As a result, they each had the same number of coins. How many coins did Tiffany have at first?
|
Tiffany |
Roshel |
Min |
Total |
Before 1 |
? |
1 u |
|
5400 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
5400 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
5 boxes |
5400 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
5400 |
3 groups = 5400
1 group = 5400 ÷ 3 = 1800
1 group = 4 boxes 4 boxes = 1800
1 box = 1800 ÷ 4 = 450
3 p = 1 group
1 p = 1800 ÷ 3 = 600
4 p = 4 x 600 = 2400
4 p = 2 u
2 u = 2400
1 u = 2400 ÷ 2 = 1200
Number of coins that Tiffany had at first
= 1 group - 1 box + 1 u
= 1800 - 450 + 1200
= 2550
Answer(s): 2550