Three girls, Marion, Fanny and Kimberly had a total of 5100 stamps. Some exchanges were made. First, Marion gave Fanny as many stamps as Fanny had. After that, Fanny gave
13 of whatever she had then to Kimberly. Finally, Kimberly gave
15 of whatever she had to Marion. As a result, they each had the same number of stamps. How many stamps did Marion have at first?
|
Marion |
Fanny |
Kimberly |
Total |
Before 1 |
? |
1 u |
|
5100 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
3 p |
|
5100 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
2 p |
|
|
Before 3 |
|
|
5 boxes |
5100 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
5100 |
3 groups = 5100
1 group = 5100 ÷ 3 = 1700
1 group = 4 boxes 4 boxes = 1700
1 box = 1700 ÷ 4 = 425
2 p = 1 group
1 p = 1700 ÷ 2 = 850
3 p = 3 x 850 = 2550
3 p = 2 u
2 u = 2550
1 u = 2550 ÷ 2 = 1275
Number of stamps that Marion had at first
= 1 group - 1 box + 1 u
= 1700 - 425 + 1275
= 2550
Answer(s): 2550