Three girls, Tiffany, Pamela and Nicole had a total of 4920 coins. Some exchanges were made. First, Tiffany gave Pamela as many coins as Pamela had. After that, Pamela gave
15 of whatever she had then to Nicole. Finally, Nicole gave
15 of whatever she had to Tiffany. As a result, they each had the same number of coins. How many coins did Tiffany have at first?
|
Tiffany |
Pamela |
Nicole |
Total |
Before 1 |
? |
1 u |
|
4920 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
4920 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
5 boxes |
4920 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
4920 |
3 groups = 4920
1 group = 4920 ÷ 3 = 1640
1 group = 4 boxes 4 boxes = 1640
1 box = 1640 ÷ 4 = 410
4 p = 1 group
1 p = 1640 ÷ 4 = 410
5 p = 5 x 410 = 2050
5 p = 2 u
2 u = 2050
1 u = 2050 ÷ 2 = 1025
Number of coins that Tiffany had at first
= 1 group - 1 box + 1 u
= 1640 - 410 + 1025
= 2255
Answer(s): 2255