Three girls, Xandra, Xylia and Linda had a total of 4440 coins. Some exchanges were made. First, Xandra gave Xylia as many coins as Xylia had. After that, Xylia gave
15 of whatever she had then to Linda. Finally, Linda gave
13 of whatever she had to Xandra. As a result, they each had the same number of coins. How many coins did Xandra have at first?
|
Xandra |
Xylia |
Linda |
Total |
Before 1 |
? |
1 u |
|
4440 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
4440 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
3 boxes |
4440 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
4440 |
3 groups = 4440
1 group = 4440 ÷ 3 = 1480
1 group = 2 boxes 2 boxes = 1480
1 box = 1480 ÷ 2 = 740
4 p = 1 group
1 p = 1480 ÷ 4 = 370
5 p = 5 x 370 = 1850
5 p = 2 u
2 u = 1850
1 u = 1850 ÷ 2 = 925
Number of coins that Xandra had at first
= 1 group - 1 box + 1 u
= 1480 - 740 + 925
= 1665
Answer(s): 1665