Three girls, Nora, Winnie and Nicole had a total of 2220 coins. Some exchanges were made. First, Nora gave Winnie as many coins as Winnie had. After that, Winnie gave
13 of whatever she had then to Nicole. Finally, Nicole gave
15 of whatever she had to Nora. As a result, they each had the same number of coins. How many coins did Nora have at first?
|
Nora |
Winnie |
Nicole |
Total |
Before 1 |
? |
1 u |
|
2220 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
3 p |
|
2220 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
2 p |
|
|
Before 3 |
|
|
5 boxes |
2220 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
4 boxes |
|
After 3 |
1 group |
1 group |
1 group |
2220 |
3 groups = 2220
1 group = 2220 ÷ 3 = 740
1 group = 4 boxes 4 boxes = 740
1 box = 740 ÷ 4 = 185
2 p = 1 group
1 p = 740 ÷ 2 = 370
3 p = 3 x 370 = 1110
3 p = 2 u
2 u = 1110
1 u = 1110 ÷ 2 = 555
Number of coins that Nora had at first
= 1 group - 1 box + 1 u
= 740 - 185 + 555
= 1110
Answer(s): 1110