Three girls, Lucy, Nicole and Linda had a total of 960 coins. Some exchanges were made. First, Lucy gave Nicole as many coins as Nicole had. After that, Nicole gave
15 of whatever she had then to Linda. Finally, Linda gave
13 of whatever she had to Lucy. As a result, they each had the same number of coins. How many coins did Lucy have at first?
|
Lucy |
Nicole |
Linda |
Total |
Before 1 |
? |
1 u |
|
960 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
5 p |
|
960 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
4 p |
|
|
Before 3 |
|
|
3 boxes |
960 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
960 |
3 groups = 960
1 group = 960 ÷ 3 = 320
1 group = 2 boxes 2 boxes = 320
1 box = 320 ÷ 2 = 160
4 p = 1 group
1 p = 320 ÷ 4 = 80
5 p = 5 x 80 = 400
5 p = 2 u
2 u = 400
1 u = 400 ÷ 2 = 200
Number of coins that Lucy had at first
= 1 group - 1 box + 1 u
= 320 - 160 + 200
= 360
Answer(s): 360