Three girls, Jade, Victoria and Pamela had a total of 2880 marbles. Some exchanges were made. First, Jade gave Victoria as many marbles as Victoria had. After that, Victoria gave
14 of whatever she had then to Pamela. Finally, Pamela gave
13 of whatever she had to Jade. As a result, they each had the same number of marbles. How many marbles did Jade have at first?
|
Jade |
Victoria |
Pamela |
Total |
Before 1 |
? |
1 u |
|
2880 |
Change 1 |
- 1 u |
+ 1 u |
|
|
After 1 |
|
2 u |
|
|
Before 2 |
|
4 p |
|
2880 |
Change 2 |
|
- 1 p |
+ 1 p |
|
After 2 |
|
3 p |
|
|
Before 3 |
|
|
3 boxes |
2880 |
Change 3 |
+ 1 box |
|
- 1 box |
|
After 3 |
|
|
2 boxes |
|
After 3 |
1 group |
1 group |
1 group |
2880 |
3 groups = 2880
1 group = 2880 ÷ 3 = 960
1 group = 2 boxes 2 boxes = 960
1 box = 960 ÷ 2 = 480
3 p = 1 group
1 p = 960 ÷ 3 = 320
4 p = 4 x 320 = 1280
4 p = 2 u
2 u = 1280
1 u = 1280 ÷ 2 = 640
Number of marbles that Jade had at first
= 1 group - 1 box + 1 u
= 960 - 480 + 640
= 1120
Answer(s): 1120